a jumping spider jumps from a log on the ground below. its height , h, in cm as a function of time ,t, in seconds since it jumped can be modeled by the function h(f)=-490t2+75t+12. when does the spider land on the ground? and what is the height of the spider 0.05 s after it jumps?

Inorder to find the height, you miust plug in 0.05s for all times (t)h(f) = -490t^2 + 75t + 12h(f) = -490 • 0.05^2 + 75 • 0.05 + 12Next follow PEMDAS from left to right. (MD reversible, AS reversible)(parentheses, exponents, multiply, divide, add, subtract)parentheses~ nothing to simplify with parenthesesexponents~ h(f) = -490 • 0.0025 + 75 • 0.05 +12multiply~  h(f) = -1.225 + 3.75 +12divide~ nothing to simplify with divisionadd~ h(f) = 14.525subtract~ nothing to simplify with subtractionDON'T FORGET UNITS!Answer: h(f) = 14.525 cm