Suggested Answer
[tex]2\dfrac{3}{4}\cdot3=\\
2\cdot3+\dfrac{3}{4}\cdot3=\\
6+\dfrac{9}{4}=\\
6+2\dfrac{1}{4}=\\
8\dfrac{1}{4}[/tex]
[tex]2\dfrac{3}{4}\cdot3=\\
2\cdot3+\dfrac{3}{4}\cdot3=\\
6+\dfrac{9}{4}=\\
6+2\dfrac{1}{4}=\\
8\dfrac{1}{4}[/tex]