y^2+4x-6x-6y+5=0
convert to standard form, find the vertex, focus, and the equation of the directrix line

I think it is :[tex]x= \frac{Y^2}{2}-3y+ \frac{5}{2} [/tex].But...not really sure

so first we group like termsy^2+4x-6x-6y+5=0y^2-6y-2x+5=0so I suspect that you might have left out a x^2 but I'll try to solve it how it isy^2-6y+5-2x=0factor y^2-6y+5what adds up to -6 and multiplies to get 5, -1 and -5(y-5)(y-1)-2x=0not sure how to procede but you could get it to this(y-5)(y-1)=2x