Chris bought 2 chicken sandwiches and 3 bowls of vegetable soup for $50, not including tax. Jim bought 1 chicken sandwich and 2 bowls of vegetable soup for$9.50, not including tax. What was the cost of a bowl of soup?

c=chicken sandwichv=bowl of vegetable soupso Chris: 2c+3v=50 andJim: 1c+2v=9.5so 2c+3v=50 and c+2v=9.5c+2v=9.5subtract 2 v from both sidesc=9.5-2vsubsitute c=9.5-2v for c in 2c+3v=502(9.5-2v)+3v=50distribute19-4v+3v=50add like terms19-v=50add v to both sides19=50+vsubtract 50 from both sides-31=vthe value of foods are never negative so there is no solution

2c + 3v = $50 ;1c + 2v =$9.50 / * 2 ;2c + 4v =$19; 2c + 3v + v =$19; $50 + v =$19; v = -$31; False, because v > 0 ;There is something wrong with this problem !