Dad is 7 times as old as his son. 10 years later, he will be three times as old as his son.find their ages?

so dad is represented by xson is represented by yso x is (x=) 7 times his son (7y)our first sentence is x=7y10 years later (x+10, y+10) he will be 3 times as old as his son (x+10=3(y+10))or 10+x=3(y+10)so our sentences arex=7yandx+10=3(y+10)first we subsitute x=7y for x in the second equation(7y)+10=3(y+10)7y+10=3(y+10)we distribute7y+10=3y+30subtract 3y from both sides4y+10=30subtract 10 from both sides4y=20divide both sides by 4y=5the son is currently 5 years oldx=7ysubsitute y=5 for y in equationx=7(5)x=35the dad is currently 35 years oldin 10 yearsdad is 45 and son is 15dad=35son=5

these are the answers son = 5dad= 35