A line passes through the point (–6, –2), and its y-intercept is (0, 1). What is the equation of the line that is perpendicular to this line and passes through the point (2, 3)?

The slope of first line is m 1= ( 1 - 0 ) / ( - 2 - ( - 6 ) );m = 1 / 4 ;Because the second line is perpendicular to the first line, m2 * m1 = - 1 ;m2 * ( 1 / 4 ) = -1; m2 = - 4 ;The equation of the second line is : y - 3 = ( - 4 )( x - 2 );y - 3 = -4x + 8 ;y = -4x + 11.

Answer:Step-by-step(- 6 1?Write an equation in slope-intercept form of the line through point (6, -1) with slope m = 4. Summary: The equation of the line passing through point (6, -1) with slope m = 4, in slope-intercept form is y = 4x - 25. explanation: