So first you should simplify it. Shawn (S) - 5 ft. per secCurtis (C) - 6 ft. per sec 1 sec 2 s 3 s 4s 5s 6sS 25 ft 30 ft 35 ft 40 ft 45 ft 50 ftC 6 ft 12 ft 18 ft 24 ft 30 ft 36 ftSo we keep going on with this table until we find two numbers that match, which is 30. Then we look back at the question. We want to find how many seconds Shawn was at when the hit the same distance as Curtis (30 ft). Yet be sure to keep in mind that Shawn started 20 seconds earlier. So the answer is 2 seconds.
Related Question in Mathematics
- On your first day of work at the Vanity Fur Grooming Shop, you groomed 3 dogs between 7:45 a.m. and 2:30 p.m., taking breaks that totaled 45 minutes. Your supervisor advises that you will be scheduling your own appointments when customers call to have their pets groomed. If you continue to work at the same rate, how much time should you allow for each grooming appointment?