so it asks you to use the quadratic formula which is when you have ax^2+bx+c=0 then you put it into the quadratic formula which is x=((-b+-√(b^2-4ac))/(2a))so 8x^2+3x=-7 add 7 to both sides8x^2+3x+7=0put into the quadratic formula8x^2+3x+7=0ax^2+bx+c=0x=((-b+-√(b^2-4ac))/(2a))x=((-3+-√(3^2-4(8)(7)))/(2(8))) solve inside of square root first3^2-4(8)(7)=pemdas 9-4(8)(7)=9-224=-215so -3+-√-215we know that square root of negative is not real and is immaginary so i must be involved√-1=i so -215=i√215so the answer is ACONTINUATIONi√215=i(15)=15i-3+-15i means -3+ or minus 15ithen solve for botom part 2(8)=16(-3+-15i)/16so the answers are (-3+15i)/16 and (-3-15i)/16
Related Question in Mathematics
- On your first day of work at the Vanity Fur Grooming Shop, you groomed 3 dogs between 7:45 a.m. and 2:30 p.m., taking breaks that totaled 45 minutes. Your supervisor advises that you will be scheduling your own appointments when customers call to have their pets groomed. If you continue to work at the same rate, how much time should you allow for each grooming appointment?