I NEED HELP FAST. DUE TOMORROW

so it asks you to use the quadratic formula which is when you have ax^2+bx+c=0 then you put it into the quadratic formula which is x=((-b+-√(b^2-4ac))/(2a))so 8x^2+3x=-7 add 7 to both sides8x^2+3x+7=0put into the quadratic formula8x^2+3x+7=0ax^2+bx+c=0x=((-b+-√(b^2-4ac))/(2a))x=((-3+-√(3^2-4(8)(7)))/(2(8)))  solve inside of square root first3^2-4(8)(7)=pemdas 9-4(8)(7)=9-224=-215so -3+-√-215we know that square root of negative is not real and is immaginary so i must be involved√-1=i so -215=i√215so the answer is ACONTINUATIONi√215=i(15)=15i-3+-15i means -3+ or minus 15ithen solve for botom part 2(8)=16(-3+-15i)/16so the answers are (-3+15i)/16 and (-3-15i)/16