using the quadratic formula b�-4b+4=0

If you need to use  the Quadratic Formula, it could also look something like this:(1)b² + (-4)b + (4) = 0These represent a, b, and c in their respective order.The equation itself is:(-b (+/-) √(b² - 4ac))/2aSo, plug 'em in:(4 (+/-) √(-4² - 4·1·4))/2·1And then solve:(4 (+/-) √(16 - 16))/2(4 (+/-) 0)/24/22

[tex]b^2-4b+4=0\\
(b-2)^2=0\\
b-2=0\\
b=2[/tex]