Suggested Answer
[tex]\dfrac{2}{3}j-\dfrac{2}{9}=\\
\dfrac{2}{3}j-\dfrac{2}{3}\cdot\dfrac{1}{3}=\\
\dfrac{2}{3}\left(j-\dfrac{1}{3}\right)
[/tex]
[tex]\dfrac{2}{3}j-\dfrac{2}{9}=\\
\dfrac{2}{3}j-\dfrac{2}{3}\cdot\dfrac{1}{3}=\\
\dfrac{2}{3}\left(j-\dfrac{1}{3}\right)
[/tex]